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6n^2+37n=455
We move all terms to the left:
6n^2+37n-(455)=0
a = 6; b = 37; c = -455;
Δ = b2-4ac
Δ = 372-4·6·(-455)
Δ = 12289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{12289}}{2*6}=\frac{-37-\sqrt{12289}}{12} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{12289}}{2*6}=\frac{-37+\sqrt{12289}}{12} $
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